Answer
$0.423\frac{rad}{s}$
Work Step by Step
We know that
$\omega _f=\sqrt{\frac{2rF\Delta \theta}{I}}$
$\omega_f=\sqrt{\frac{2RF\Delta \theta}{\frac{1}{2}MR^2}}$
$\omega_f=\sqrt{\frac{2)(2.74)(36.1)(32.5\times \pi rev/180^{\circ})}{\frac{1}{2}(167)(2.74)^2}}$
$\omega_f=0.423\frac{rad}{s}$