Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 11 - Rotational Dynamics and Static Equilibrium - Problems and Conceptual Exercises - Page 371: 79

Answer

$0.423\frac{rad}{s}$

Work Step by Step

We know that $\omega _f=\sqrt{\frac{2rF\Delta \theta}{I}}$ $\omega_f=\sqrt{\frac{2RF\Delta \theta}{\frac{1}{2}MR^2}}$ $\omega_f=\sqrt{\frac{2)(2.74)(36.1)(32.5\times \pi rev/180^{\circ})}{\frac{1}{2}(167)(2.74)^2}}$ $\omega_f=0.423\frac{rad}{s}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.