Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 1 - Introduction to Physics - Problems and Conceptual Exercises - Page 15: 21

Answer

$V=18~ft^{3}$

Work Step by Step

See conversion factors (inside front cover). $1~cubit=17.7~in$, $1~in=2.54\times10^{-2}~m$, and $1~m=3.281~ft$ $L=2.5~cubits$ and $W=H=1.5~cubits$. $V=L\times W\times H=(2.5~cubits)(1.5~cubits)(1.5~cubits)=5.6~cubits^{3}$ $V=(5.6~cubits^{3})(\frac{17.7~in}{1~cubit})^{3}(\frac{2.54\times10^{-2}~m}{1~in})^{3}(\frac{3.281~ft}{1~m})^{3}=18~ft^{3}$
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