Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 1 - Introduction to Physics - Problems and Conceptual Exercises - Page 15: 20

Answer

(a) $V=4.83\times10^{8}~ft^{3}$ (b) $V=1.37\times10^{7}~m^{3}$

Work Step by Step

See conversion factors (inside front cover). (a) $1~yd=3~ft$ and $1~m=3.281~ft$ $L=(631~m)(\frac{3.281~ft}{1~m})=2.07\times 10^{3}~ft$ $W=(707~yd)(\frac{3~ft}{1~yd})=2.12\times10^{3}~ft$ $H=110~ft=1.10\times10^{2}~ft$ $V=L\times W\times H=(2.07\times 10^{3}~ft)(2.12\times10^{3}~ft)(1.10\times10^{2}~ft)=4.83\times10^{8}~ft^{3}$ (b) $V=(4.83\times10^{8}~ft^{3})(\frac{1~m}{3.281~ft})^{3}=1.37\times10^{7}~m^{3}$
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