Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 1 - Introduction to Physics - Problems and Conceptual Exercises - Page 15: 9

Answer

p = -2

Work Step by Step

The given relation is $a=2xt^p$....eq(1) We know that the dimension of distance $x=[L]$ The dimension of acceleration is $[LT^{-2}]$ and the dimension of time $t=[T]$ and the number $2$ is constant and dimensionless. Now eq(1) becomes $[LT^{-2}]=[L][T]^p$ Comparing both sides, we obtain: $p=-2$
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