Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 8 - Rotational Motion - Problems - Page 223: 36

Answer

See answers.

Work Step by Step

a. First find the angular acceleration. $$\alpha = \frac{\Delta \omega}{\Delta t}=\frac{v/r}{t}=\frac{(8.5m/s)/(0.31m)}{0.38s}\approx 72rad/s^2$$ b. Apply Newton’s second law. The torque is the moment of inertia multiplied by the angular acceleration. $$Frsin \theta=I \alpha$$ $$F=\frac{I \alpha}{r sin \theta}=\frac{m_{ball}(0.31m)^2+\frac{1}{3}m_{arm}(0.31m)^2}{(0.025m)sin 90}\alpha$$ $$F=619.5N\approx 620N$$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.