Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 8 - Rotational Motion - Problems: 33

Answer

$1.2 \times 10^{-10}m$.

Work Step by Step

Treat the 2 oxygen molecules like point masses of mass M/2, each a distance D/2 from the axis of rotation. $$I=(M/2)(D/2)^2+(M/2)(D/2)^2=\frac{1}{4}MD^2=1.9 \times 10^{-46} kg \cdot m^2$$ Use the given M and solve for $D=1.2 \times 10^{-10}m$.
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