Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 8 - Rotational Motion - Problems: 31

Answer

$0.12 kg \cdot m^2$.

Work Step by Step

Treat the rim and tire like a hoop, with all of the mass at a distance R. We ignore the hub because the mass is located at the axis, with a very small r (approximately r = 0). $$I=MR^2= (1.1 kg)(0.335m)^2=0.12 kg \cdot m^2$$
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