## Physics: Principles with Applications (7th Edition)

$0.12 kg \cdot m^2$.
Treat the rim and tire like a hoop, with all of the mass at a distance R. We ignore the hub because the mass is located at the axis, with a very small r (approximately r = 0). $$I=MR^2= (1.1 kg)(0.335m)^2=0.12 kg \cdot m^2$$