Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 6 - Work and Energy - General Problems - Page 168: 91

Answer

a) $d=0.39m$ b) $\mu_s<0.53$ c) $1.38\frac{m}{s}$

Work Step by Step

a) $E_{Ki}=E_{Pf}+W_f$ $\frac{mv^2}{2}=mgd\sin(\phi)+0.25d\times F_N$ $F_N=mg\cos(\phi)$ $d=\frac{v^2}{2g(\mu_k\cos(\phi)+\sin(\phi))}=\frac{(2.3\frac{m}{s})^2}{2(9.8\frac{m}{s^2})(0.25\cos(28.0^o)+\sin(28.0^o))}$ $=0.39m$ b) $F_{sf}
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