Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 6 - Work and Energy - General Problems: 81

Answer

340 W.

Work Step by Step

The work done on the athlete is the change in PE, mgh. The power is the work done divided by time. $$P=\frac{W}{t}=\frac{mgh}{t}=\frac{(62 kg)(9.80\frac{m}{s^2})(5.0 m)}{9.0s}=340 W$$
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