Answer
340 W.
Work Step by Step
The work done on the athlete is the change in PE, mgh. The power is the work done divided by time.
$$P=\frac{W}{t}=\frac{mgh}{t}=\frac{(62 kg)(9.80\frac{m}{s^2})(5.0 m)}{9.0s}=340 W$$
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