Answer
$F_E=9.6\times10^{17}N$
$\frac{F_E}{F_{SE}}=2.7\times10^{-5}$
Work Step by Step
$F_G=G\frac{m_1m_2}{r^2}$
Assuming right is positive and left is negative, the gravitational force of Jupiter and Saturn will be positive while the gravitational field of Venus and the sun will be negative.
$m_E=5.98\times10^{24}kg$
$F_{SE}=-6.67\times10^{-11}\frac{Nm^2}{kg^2}\frac{1.99\times10^{30}kg\times 5.98\times10^{24}kg}{(150\times10^9m)^2}$
$=-3.53\times10^{22}N$
$F_{VE}=-6.67\times10^{-11}\frac{Nm^2}{kg^2}\frac{0.815\times 5.98\times10^{24}kg\times 5.98\times10^{24}kg}{(42\times10^9m)^2}$
$=-1.10\times10^{18}N$
$F_{JE}=6.67\times10^{-11}\frac{Nm^2}{kg^2}\frac{318\times 5.98\times10^{24}kg\times 5.98\times10^{24}kg}{(628\times10^9m)^2}=1.92\times10^{18}N$
$F_{SE}=6.67\times10^{-11}\frac{Nm^2}{kg^2}\frac{95.1\times 5.98\times10^{24}kg\times 5.98\times10^{24}kg}{(1280\times10^9m)^2}=1.38\times10^{17}N$
$F_E=-1.10\times10^{24}N+1.92\times10^{24}N+1.38\times10^{23}N=9.6\times10^{17}N$
$\frac{F_E}{F_{SE}}=\frac{9.6\times10^{17}N}{3.53\times10^{22}N}=2.7\times10^{-5}$
