Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 5 - Circular Motion; Gravitation - Problems: 37

Answer

$27.4 \frac{m}{s^2}$

Work Step by Step

Equation 5-5 gives g, the acceleration due to gravity near the surface of Earth. If the mass of Earth were to increase by 2.80, other things being equal, g would increase by the same factor. $$(2.80)(9.80 \frac{m}{s^2}) = 27.4 \frac{m}{s^2}$$
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