Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 5 - Circular Motion; Gravitation - Problems - Page 134: 44

Answer

$g = 6.67 \times 10^{12} ~m/s^2$

Work Step by Step

Let's use $2.0 \times 10^{30}~kg$ as the mass of the sun. The mass of the neutron star is $10^{31}~kg$: $g = \frac{GM}{r^2} = \frac{(6.67 \times 10^{-11} ~N \cdot m^2/kg^2)(10^{31}~kg)}{(10^4 ~m)^2}$ $g = 6.67 \times 10^{12} ~m/s^2$
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