Answer
36.9 degrees
Work Step by Step
The light is coming from air to water. Apply equation 24–6b.
$$tan\theta_p=n_{water}=1.33$$
$$\theta_p=tan^{-1}1.33=53.1^{\circ}$$
This angle is measured from the normal (see Figure 24–48). The angle of the sun above the horizon is the complement of that angle, $90^{\circ}-53.1^{\circ}=36.9^{\circ}$.
