Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 24 - The Wave Nature of Light - General Problems - Page 711: 87

Answer

580 nm

Work Step by Step

The lines on the wing act like a reflection grating, discussed in section 24-6. Assume that the first order reflection is the one we see, m = 1. Use equation 24–4. $$d sin \theta = m \lambda $$ Apply this to the first order fringe. $$d = \frac{m \lambda}{ sin \theta }$$ $$d = \frac{1(480\times10^{-9}m)}{sin 56^{\circ}}$$ $$d = 5.8\times10^{-7}m $$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.