Answer
$6.25\times10^{-4}V/m$, $1.04\times10^{-9}W/m^2$.
Work Step by Step
Find the electric field strength from the specified rms voltage, and the antenna’s length.
$$E_{rms}=\frac{V_{rms}}{d}=\frac{0.00100V}{1.60m}=6.25\times10^{-4}V/m$$
Use that electric field to calculate the intensity. The energy per unit area per unit time is the magnitude of the average intensity, equation 22–8.
$$\overline{I}=\frac{P}{A}=\frac{1}{2}\epsilon_ocE_o^2=\frac{1}{2}\epsilon_oc(\sqrt{2}E_{rms})^2$$
$$=\epsilon_ocE_{rms}^2=\epsilon_oc(\frac{V_{rms}}{d})^2$$
$$=(8.85\times10^{-12} C^2/(N\cdot m^2))(3.00\times10^8m/s) (\frac{0.00100V}{1.60m})^2$$
$$= 1.04\times10^{-9}W/m^2$$
