Answer
$3.0\times10^1m^2$
Work Step by Step
Using the hint, the intensity from a point source (such as a faraway sun) is inversely proportional to the square of the distance from the source. Look up the distance from the sun to Jupiter.
$$\frac{I_E}{I_J}=\frac{r_{sun-J}^2}{ r_{sun-E}^2}$$
$$\frac{I_E}{I_J}=\frac{(8.16\times10^{11}m)^2}{(1.496\times10^{11}m)^2}=29.8$$
Sunlight is about 30 times as intense at the Earth as it is at Jupiter, so a solar panel near Jupiter would need to be about $3.0\times10^1$ times larger than a $1.0 m^2$ panel near Earth to collect the same amount of radiation.