Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 22 - Electromagnetic Waves - Problems - Page 642: 32

Answer

$3.0\times10^1m^2$

Work Step by Step

Using the hint, the intensity from a point source (such as a faraway sun) is inversely proportional to the square of the distance from the source. Look up the distance from the sun to Jupiter. $$\frac{I_E}{I_J}=\frac{r_{sun-J}^2}{ r_{sun-E}^2}$$ $$\frac{I_E}{I_J}=\frac{(8.16\times10^{11}m)^2}{(1.496\times10^{11}m)^2}=29.8$$ Sunlight is about 30 times as intense at the Earth as it is at Jupiter, so a solar panel near Jupiter would need to be about $3.0\times10^1$ times larger than a $1.0 m^2$ panel near Earth to collect the same amount of radiation.
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