Answer
Channel 2: $\lambda=5.56m$
Channel 51: $\lambda=0.434m$
Work Step by Step
Use equation 22–4, $c=\lambda f$
Channel 2:
$$\lambda=\frac{c}{f}=\frac{3.00\times10^8m/s }{54.0\times10^6Hz}$$
$$\lambda=5.56m$$
Channel 51:
$$\lambda=\frac{c}{f}=\frac{3.00\times10^8m/s }{692\times10^6Hz}$$
$$\lambda=0.434m$$
