Answer
No
Work Step by Step
let $t_1$ be the time taken by the cat to leap through window and $t_2$ be time taken by dog to reach the window.
for cat
$ s= ut _1+\frac{1}{2} at_1^2$
$1.5 = 0 + \frac{1}{2} (0.85)t_1^2$
$t_2 =3.53s^2$
$t_1 = 1.88s$
for dog
$ s= ut_2 +\frac{1}{2} at_2^2$
$3 = 1.5t_2 -\frac{1}{2} (0.1)t_2^2$
$t_2^2 -30t_2 +60 =0$
$ t_2 =2.15s$
since $t_2 >t_1$ so dog will no catch cat.
