Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (3rd Edition)

Published by Pearson
ISBN 10: 0321740904
ISBN 13: 978-0-32174-090-8

Chapter 36 - Relativity - Exercises and Problems - Page 1099: 39

Answer

(a) $E = 1.8\times 10^{16}~J$ (b) The energy equivalent exceeds the food energy by a factor of $9.0\times 10^9$

Work Step by Step

(a) We can find the energy equivalent of the mass: $E = mc^2$ $E = (0.20~kg)(3.0\times 10^8~m/s)^2$ $E = 1.8\times 10^{16}~J$ (b) $\frac{1.8\times 10^{16}~J}{2\times 10^6~J} = 9.0\times 10^9$ The energy equivalent exceeds the food energy by a factor of $9.0\times 10^9$
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