Answer
a)$I = 11.57A$
b)$R=10.37\Omega$
Work Step by Step
energy consumed for one month= 1000kWh
power = energy/ time
Power = $\frac{1000 *1000 Wh}{30 *24h} =1388.9 W$
a)power =$VI 120V* I $
$120V*I =1388.9W$
$I= \frac{1388.9}{120}A = 11.57A$
b) power =$\frac{V^2}{R}$
$\frac{(120V)^2}{R}= 1388.9W$
$R =\frac{1388.9}{14400} \Omega$
$R=10.37\Omega$
