Answer
$V_{12} = 8V$
$V_{33} = 22V$
Work Step by Step
Equivalent resistance of the circuit
$R_{eq} = 12\Omega + 33\Omega =45\Omega$
Current in circuit
$I =\frac{v}{R_{eq}} = \frac{30V}{45\Omega} =\frac{2}{3}A$
now potential difference across $12\Omega$ is
$V_{12} =IR= \frac{2}{3} *12V = 8V$
and potential difference across $33\Omega $ is
$V_{33} = IR = \frac{2}{3}*33 V = 22V$
