Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (3rd Edition)

Published by Pearson
ISBN 10: 0321740904
ISBN 13: 978-0-32174-090-8

Chapter 31 - Fundamentals of Circuits - Exercises and Problems - Page 915: 4

Answer

See the detailed answer below.

Work Step by Step

$$\color{blue}{\bf [a]}$$ It is obvious, from the given figure, that the two batteries are in series, so the direction of the current in this circuit loop is clockwise. So the direction of the current in the resistors is toward the right. Its magnitude is given by Ohm's law, $$\Delta V_{net}=IR$$ $$I=\dfrac{\Delta V_{net}}{R}$$ Plug the known; $$I=\dfrac{6+3}{18}=\color{red}{\bf 0.5}\;\rm A$$ This circuit is too simple to use Kirchhoff's loop law, but you can indeed use it. $$\color{blue}{\bf [b]}$$ The author assumed that the left lower corner is the 0-V.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.