Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (3rd Edition)

Published by Pearson
ISBN 10: 0321740904
ISBN 13: 978-0-32174-090-8

Chapter 26 - The Electric Field - Exercises and Problems: 15

Answer

$Q = 80~nC$

Work Step by Step

We can use the equation for the electric field strength around a spherical shell to find the charge $Q$: $E = \frac{kQ}{r^2}$ $Q = \frac{r^2~E}{k}$ $Q = \frac{(0.12~m)^2(50,000~N/C)}{9.0\times 10^9~N~m^2/C^2}$ $Q = 80~nC$
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