Physics for Scientists and Engineers: A Strategic Approach with Modern Physics (3rd Edition)

Published by Pearson
ISBN 10: 0321740904
ISBN 13: 978-0-32174-090-8

Chapter 18 - Heat Engines and Refrigerators - Exercises and Problems - Page 549: 2

Answer

$ \eta = 33.33\%$

Work Step by Step

We know that $ W=Q_1 -Q_2$ $200J = Q_1 -400J$ $ Q_1 = 600J$ Also $ \eta = \frac{W}{Q_1}$ $\eta = \frac{200J}{600J}$ $ \eta = 33.33\%$
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