Answer
$41\;\rm J$
Work Step by Step
We know that the work done by the gas per cycle is the enclosed area under the $p-V$ curve.
Hence,
$$W_{out}={\rm \;Area} $$
And we can see that the enclosed area under the $P_V$ curve is a right triangle.
$$W_{out}=\frac{1}{2}(600-200)\times 10^{-6}(3-1)\times 1.013\times 10^5 $$
$$W_{out}=40.52\;\rm J\approx \color{red}{\bf 41}\;\rm J$$
