Answer
(a) 1.5 mol
(b) 3 mol
(c) 3 mol
(d) 96 mol
Work Step by Step
(a) Calculating how much product can be made based on the amount of each reactant, we have
$1\,mol\,A\times\frac{3\,mol\,C}{1\,mol\,A}=3\,mol\,C$
$1\,mol\,B\times\frac{3\,mol\,C}{2\,mol\,B}=1.5\,mol\,C$
Since $1\,mol\,B$ makes the least amount of product, it is the limiting reactant.
Theoretical yield is the maximum amount of product that can be made in a reaction based on the amount of limiting reactant.
Therefore, theoretical yield= $1.5\,mol$.
(b) Calculating how much product can be made based on the amount of each reactant, we have
$2\,mol\,A\times\frac{3\,mol\,C}{1\,mol\,A}=6\,mol\,C$
$2\,mol\,B\times\frac{3\,mol\,C}{2\,mol\,B}=3\,mol\,C$
Since $2\,mol\,B$ makes the least amount of product, it is the limiting reactant.
Theoretical yield= $3\,mol$
(c) Calculating how much product can be made based on the amount of each reactant, we have
$1\,mol\,A\times\frac{3\,mol\,C}{1\,mol\,A}=3\,mol\,C$
$3\,mol\,B\times\frac{3\,mol\,C}{2\,mol\,B}=4.5\,mol\,C$
Since $1\,mol\,A$ makes the least amount of product, it is the limiting reactant.
Theoretical yield= $3\,mol$
(d) Calculating how much product can be made based on the amount of each reactant, we have
$32\,mol\,A\times\frac{3\,mol\,C}{1\,mol\,A}=96\,mol\,C$
$68\,mol\,B\times\frac{3\,mol\,C}{2\,mol\,B}=102\,mol\,C$
Since $32\,mol\,A$ makes the least amount of product, it is the limiting reactant.
Theoretical yield= $96\,mol$