Introductory Chemistry (5th Edition)

Published by Pearson
ISBN 10: 032191029X
ISBN 13: 978-0-32191-029-5

Chapter 8 - Quantities in Chemical Reactions - Exercises - Problems - Page 276: 45

Answer

(a) 1.5 mol (b) 3 mol (c) 3 mol (d) 96 mol

Work Step by Step

(a) Calculating how much product can be made based on the amount of each reactant, we have $1\,mol\,A\times\frac{3\,mol\,C}{1\,mol\,A}=3\,mol\,C$ $1\,mol\,B\times\frac{3\,mol\,C}{2\,mol\,B}=1.5\,mol\,C$ Since $1\,mol\,B$ makes the least amount of product, it is the limiting reactant. Theoretical yield is the maximum amount of product that can be made in a reaction based on the amount of limiting reactant. Therefore, theoretical yield= $1.5\,mol$. (b) Calculating how much product can be made based on the amount of each reactant, we have $2\,mol\,A\times\frac{3\,mol\,C}{1\,mol\,A}=6\,mol\,C$ $2\,mol\,B\times\frac{3\,mol\,C}{2\,mol\,B}=3\,mol\,C$ Since $2\,mol\,B$ makes the least amount of product, it is the limiting reactant. Theoretical yield= $3\,mol$ (c) Calculating how much product can be made based on the amount of each reactant, we have $1\,mol\,A\times\frac{3\,mol\,C}{1\,mol\,A}=3\,mol\,C$ $3\,mol\,B\times\frac{3\,mol\,C}{2\,mol\,B}=4.5\,mol\,C$ Since $1\,mol\,A$ makes the least amount of product, it is the limiting reactant. Theoretical yield= $3\,mol$ (d) Calculating how much product can be made based on the amount of each reactant, we have $32\,mol\,A\times\frac{3\,mol\,C}{1\,mol\,A}=96\,mol\,C$ $68\,mol\,B\times\frac{3\,mol\,C}{2\,mol\,B}=102\,mol\,C$ Since $32\,mol\,A$ makes the least amount of product, it is the limiting reactant. Theoretical yield= $96\,mol$
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