Answer
(a) 1 mol A
(b) 3 mol B
(c) 0.5 mol A
(d) 24 mol A
Work Step by Step
(a) Calculating how much product can be made based on the amount of each reactant, we have
$1\,mol\,A\times\frac{1\,mol\,C}{1\,mol\,A}=1\,mol\,C$
$4\,mol\,B\times\frac{1\,mol\,C}{3\,mol\,B}=1.33\,mol\,C$
Since $1\,mol\,A$ makes the least amount of product, it is the limiting reactant.
(b) Calculating how much product can be made based on the amount of each reactant, we have
$2\,mol\,A\times\frac{1\,mol\,C}{1\,mol\,A}=2\,mol\,C$
$3\,mol\,B\times\frac{1\,mol\,C}{3\,mol\,B}=1\,mol\,C$
Since $3\,mol\,B$ makes the least amount of product, it is the limiting reactant.
(c) Calculating how much product can be made based on the amount of each reactant, we have
$0.5\,mol\,A\times\frac{1\,mol\,C}{1\,mol\,A}=0.5\,mol\,C$
$1.6\,mol\,B\times\frac{1\,mol\,C}{3\,mol\,B}=0.533\,mol\,C$
Since $0.5\,mol\,A$ makes the least amount of product, it is the limiting reactant.
(d) Calculating how much product can be made based on the amount of each reactant, we have
$24\,mol\,A\times\frac{1\,mol\,C}{1\,mol\,A}=24\,mol\,C$
$75\,mol\,B\times\frac{1\,mol\,C}{3\,mol\,B}=25\,mol\,C$
Since $24\,mol\,A$ makes the least amount of product, it is the limiting reactant.