Answer
(a) 2 mol
(b) 2 mol
(c) 4 mol
(d) 3.33 mol
Work Step by Step
(a) Calculating how much product can be made based on the amount of each reactant, we have
$2\,mol\,A\times\frac{2\,mol\,C}{2\,mol\,A}=2\,mol\,C$
$4\,mol\,B\times\frac{2\,mol\,C}{3\,mol\,B}=2.67\,mol\,C$
Since $2\,mol\,A$ makes the least amount of product, it is the limiting reactant.
Theoretical yield is the maximum amount of product that can be made in a reaction based on the amount of limiting reactant.
Therefore, theoretical yield= $2\,mol$.
(b) Calculating how much product can be made based on the amount of each reactant, we have
$3\,mol\,A\times\frac{2\,mol\,C}{2\,mol\,A}=3\,mol\,C$
$3\,mol\,B\times\frac{2\,mol\,C}{3\,mol\,B}=2\,mol\,C$
Since $3\,mol\,B$ makes the least amount of product, it is the limiting reactant.
Theoretical yield= $2\,mol$
(c) Calculating how much product can be made based on the amount of each reactant, we have
$5\,mol\,A\times\frac{2\,mol\,C}{2\,mol\,A}=5\,mol\,C$
$6\,mol\,B\times\frac{2\,mol\,C}{3\,mol\,B}=4\,mol\,C$
Since $6\,mol\,B$ makes the least amount of product, it is the limiting reactant.
Theoretical yield= $4\,mol$
(d) Calculating how much product can be made based on the amount of each reactant, we have
$4\,mol\,A\times\frac{2\,mol\,C}{2\,mol\,A}=4\,mol\,C$
$5\,mol\,B\times\frac{2\,mol\,C}{3\,mol\,B}=3.33\,mol\,C$
Since $5\,mol\,B$ makes the least amount of product, it is the limiting reactant.
Theoretical yield= $3.33\,mol$
