Introductory Chemistry (5th Edition)

Published by Pearson
ISBN 10: 032191029X
ISBN 13: 978-0-32191-029-5

Chapter 2 - Measurement and Problem Solving - Exercises - Problems - Page 52: 77

Answer

$5.08\times10^{5}$ km $0.508$ Gm $0.000508$ or $5.08\times10^{-4}$ Tm $2.7976\times10^{10}$ m $2.7976\times10^{7}$ km $27.976$ Gm $0.027976$ or $2.7976\times10^{-2}$ Tm $1.77\times10^{12}$ m $1.77\times10^{9}$ km $1.77\times10^{6}$ Mm $1.77\times10^{3}$ or $1770$ Gm $1.5\times10^{8}$ m $150$ Mm $0.15$ Gm $0.00015$ or $1.5\times10^{-4}$ Tm $4.23\times10^{11}$ m $4.23\times10^{8}$ km $4.23\times10^{5}$ Mm $0.423$ Tm

Work Step by Step

Tera(T) = $10^{12}$ Giga(G) = $10^{9}$ Mega(M) = $10^{6}$ kilo(k) = $10^{3}$ hecto(h) = $10^{2}$ deca(da) = $10^{1}$ deci(d) = $10^{-1}$ centi(c) = $10^{-2}$ milli(m) = $10^{-3}$ micro(μ) = $10^{-6}$ nano(n) = $10^{-9}$ pico(p) = $10^{-12}$
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