Introductory Chemistry (5th Edition)

Published by Pearson
ISBN 10: 032191029X
ISBN 13: 978-0-32191-029-5

Chapter 2 - Measurement and Problem Solving - Exercises - Problems - Page 52: 87

Answer

a) $1\times10^{6} m^{2}$ b) $1\times10^{-6} m^{3}$ c) $1\times10^{-9} m^{3}$

Work Step by Step

a) Using the conversion factor of $1 km^{2} = 1\times10^{6} m^{2}$, therefore we simply multiply 1 by $\times10^{6}$. b) Using the conversion factor of $1 cm^{3} = 1\times10^{-6} m^{3}$, therefore we simply multiply 1 by $\times10^{-6}$. c) Using the conversion factor of $1 mm^{3} = 1\times10^{-9} m^{3}$, therefore we simply multiply 1 by $\times10^{-9}$.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.