Introductory Chemistry (5th Edition)

Published by Pearson
ISBN 10: 032191029X
ISBN 13: 978-0-32191-029-5

Chapter 2 - Measurement and Problem Solving - Exercises - Problems - Page 52: 78

Answer

$0.131$ ms $131000$ ns $1.31\times10^{8}$ ps $1.26\times10^{-11}$ s $1.26\times10^{-8}$ ms $1.26\times10^{-5}$ μs $1.26\times10^{-2}$ ns $1.55\times10^{-7}$ s $1.55\times10^{-4}$ ms $1.55\times10^{-1}$ μs $1.55\times10^{5}$ ps $1.99\times10^{-6}$ s $1.99$ μs $1990$ ns $1.99\times10^{6}$ ps $8.66\times10^{-11}$ s $8.66\times10^{-8}$ ms $8.66\times10^{-2}$ ns $86.6$ ps

Work Step by Step

Tera(T) = $10^{12}$ Giga(G) = $10^{9}$ Mega(M) = $10^{6}$ kilo(k) = $10^{3}$ hecto(h) = $10^{2}$ deca(da) = $10^{1}$ deci(d) = $10^{-1}$ centi(c) = $10^{-2}$ milli(m) = $10^{-3}$ micro(μ) = $10^{-6}$ nano(n) = $10^{-9}$ pico(p) = $10^{-12}$
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