Introductory Chemistry (5th Edition)

Published by Pearson
ISBN 10: 032191029X
ISBN 13: 978-0-32191-029-5

Chapter 17 - Radioactivity and Nuclear Chemistry - Exercises - Cumulative Problems - Page 639: 88

Answer

Nuclear equations are as follows:

Work Step by Step

Sum of mass number on the left side of a nuclear equation will be always equal to sum of mass number on the right side of the nuclear equation. Similarly, Sum of atomic number on the left side will be equal to the sum of atomic number on the right side for a nuclear equation. Now, let's complete every nuclear equation. See the 1st equation. Total mass number on the left side = 27+4 = 31. So, total number on the right side will also be equal to 31. So, the questioned element will have mass number = 31-1 =30. Similarly, Total atomic number on the left side = 13+2 = 15. So, on the right side total atomic number will be 15. Therefore, the questioned element on the right side will have atomic number = 15. So, the questioned element in the 1st nuclear equation will be P-30 (Atomic number 15). For 2nd equation: Total mass number on the right side = 29+4 = 33. Total atomic number on the right side = 14+2 = 16. So, total mass number on the left side will also be 33 and total atomic number on the left side will be 16. Hence, the questioned element on the left side will have atomic number = 16 and mass number = 33-1 = 32. So, the questioned element is S-32 (Atomic number 16). For 3rd equation: Total mass number on the left side = 241. Total atomic number on the left side = 95. So, the questioned element on the right side will have atomic number = (95-93) = 2 and mass number = (241-237) = 4. So, the questioned element is He-4 (alpha particle). Now, we can complete each nuclear equation.
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