Answer
Complete nuclear equation for each reaction is as follows:
Work Step by Step
The sum of mass number on the left side of a nuclear equation is always equal to the sum of mass number on the right side of the equation. Similarly, sum of atomic number on the left side of the nuclear equation is equal to the sum of atomic number on the right side of the equation.
Now, let's see the first equation. Here, on the left side sum of mass number is = (1+9) = 10. and sum of atomic number = (1+4) = 5.
So, the sum of mass number on the right side will also be 10. Now, On the right side we have mass number 4 for 'He'. So, the new element will have mass number= 10-4 = 6. Similarly, the sum of atomic number on the right side will also be 5. On the right side we have atomic number 2 for 'He'. So, the new element will have atomic number= 5-2 = 3.
So, the new element is Li (Atomic number 3; mass number 6). We can write this element in symbolic form and complete the equation.
For the 2nd equation, total mass number on the right side = 272+1 = 273.
Therefore, total mass number on the left side will also be 273.
We can see that on the left side we have mass number 209 for 'Bi'. So, the questioned element will have mass number 273-209 = 64.
Total atomic number on the right side = 111+0 = 111.
So, the questioned element on the left side will have atomic number = 111-83 = 28.
So, the questioned element is Ni (Atomic number 28 ; mass number 64) which can be written in symbolic form in the equation.
In the third equation, total mass number on the left side = 179+0 = 179. So, the total mass number on the right side will also be 179.
Total Atomic number on the left side = 74+(-1) = 73.
So, total atomic number on the right side will also be 73.
So, the questioned element has the atomic number 73 and mass number 179.
The element is W (Atomic number 73 ; mass number 179) which can be represented as symbolic form in the equation.
