Introductory Chemistry (5th Edition)

Published by Pearson
ISBN 10: 032191029X
ISBN 13: 978-0-32191-029-5

Chapter 13 - Solutions - Exercises - Problems - Page 480: 52

Answer

a. 2.9x$10^2$ g solution. b. 3.8x$10^2$ g solution. c. 96 g solution.

Work Step by Step

Mass percent is the number of grams of solute per 100g of solution. a. So a solution with a concentration of 4.1% sucrose per 100 g of solution. Hence 12 g of sucrose present: (100g solution/4.1 g NaCl)x12g sucrose = 2.9x$10^2$ g solution. b. So a solution with a concentration of 3.2% sucrose per 100 g of solution. Hence 12 g of sucrose present: (100g solution/3.2 g NaCl)x12g sucrose = 3.8x$10^2$ g solution. c. So a solution with a concentration of 12.5% sucrose per 100 g of solution. Hence 12 g of sucrose present: (100g solution/12.5 g NaCl)x12g sucrose = 96 g solution.
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