Introductory Chemistry (5th Edition)

Published by Pearson
ISBN 10: 032191029X
ISBN 13: 978-0-32191-029-5

Chapter 13 - Solutions - Exercises - Problems - Page 480: 51

Answer

(a) $2.6\,kg$ (b) $1.0\times10^{2}\,g$ (c) $18\,g$

Work Step by Step

Mass % of NaCl= $\frac{\text{Mass of NaCl}}{\text{Mass of NaCl solution}}\times100\%$ $\implies \text{Mass of NaCl solution}=\frac{\text{Mass of NaCl}}{\text{Mass % of NaCl}}\times100\%$ (a) $\text{Mass of NaCl solution}=\frac{\text{Mass of NaCl}}{\text{Mass % of NaCl}}\times100\%$ $=\frac{1.5\,g}{0.058}\times100=2.6\times10^{3}\,g=2.6\,kg$ (b) $\text{Mass of NaCl solution}=\frac{1.5\,g}{1.46}\times100=1.0\times10^{2}\,g$ (c) $\text{Mass of NaCl solution}=\frac{1.5\,g}{8.44}\times100=18\,g$
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