Answer
0.01035 %
Work Step by Step
It is given that a soft drink contains 32 mg of sodium in 309 g of $H_{2}O$.
Mass percent = (Mass solute X 100)/ (Mass solute + Mass solvent)
= (0.032 X 100)/(309 + 0.032)
= 3.2/309.032
= 0.01035 %
Introductory Chemistry (5th Edition)
by Tro, Nivaldo J.
Published by
Pearson
ISBN 10:
032191029X
ISBN 13:
978-0-32191-029-5
Chapter 13 - Solutions - Exercises - Problems - Page 480: 44
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