Answer
The final pressure of the sample is $P_{2} = 876.56 mm Hg$
Work Step by Step
Using the combined gas law with the involved quantities we can see that $\frac{P_{1}V_{1}}{T_{1}}=\frac{P_{2}V_{2}}{T_{2}}$, however since the volume remains constant, the expression can be simplified to $\frac{P_{1}}{T_{1}}=\frac{P_{2}}{T_{2}}$
Since the question asks for the final pressure, we must solve for $P_{2}$. For this question we must also convert the two temperatures into the standard units of Kelvin by simply adding 273.15 to the Celsius values.
$28^{\circ}C + 273.15 = 301.15 K$
$86^{\circ}C + 273.15 = 359.15 K$
Rearranging for $P_{2}$, we get:
$\frac{P_{1}T_{2}}{T_{1}}=P_{2}.$ Therefore, $\frac{735 mm Hg \times 359.15 K}{301.15 K}=P_{2}.$
$P_{2} = 876.56 mm Hg$
