Answer
The final pressure is ${P_{2}} = 228.1 kPa$ or $1710.9 mm Hg$
Work Step by Step
Using the combined gas law with the involved quantities we can see that
$\frac{P_{1}V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}}$.
Since the question asks for the final pressure, we must solve for $P_{2}$
Next we must convert the pressure into standard units of kPa by using the conversion factor below:
$725 mm Hg\times\frac{1 kPa}{7.50062 mm Hg} = 96.66 kPa$
Rearranging for $P_{2}$, we get:
$\frac{P_{1}V_{1}{T_{2}}}{T_{1}{V_{2}}} = {P_{2}}$. Therefore, $\frac{96.66 kPa\times 28.4 L \times375 K }{305 K\times 14.8 L} = {P_{2}}$.
$${P_{2}} = 228.1 kPa$$
