Introductory Chemistry (5th Edition)

Published by Pearson
ISBN 10: 032191029X
ISBN 13: 978-0-32191-029-5

Chapter 11 - Gases - Exercises - Problems - Page 402: 41

Answer

The final volume of the gas is 58.9 mL

Work Step by Step

The Charle's gas law defines the relationship between temperature and volume. According to this, the volume of gas is directly proportional to its temperature at a constant pressure. $\frac{V}{T}$ = constant Therefore as the temperature of a gas increases the volume of the gas increases and as the temperature of a gas decreases the volume of the gas decreases. For a gas, we can create two equations with $V_{1}$ as the initial volume of the gas and $V_{2}$ as the final volume of the gas. $V_{1}$= 48.3 mL, $T_{1}$= 295 K $T_{2}$= 360 K. $\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}$ rearrange the equation for $V_{2}$ $V_{2} = \frac{T_{2}V_{1}}{T_{1}}$ Plug in the values for the variables $V_{2} = \frac{360 K \times 48.3 mL}{295 K}$ Solve using a calculator $V_{2} = 58.9 mL$
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