General Chemistry 10th Edition

Published by Cengage Learning
ISBN 10: 1-28505-137-8
ISBN 13: 978-1-28505-137-6

Chapter 1 - Chemistry and Measurement - Questions and Problems - Page 35: 1.68

Answer

a. 6.20 x $10^{3}$ m b. 1.98 x $10^{-9}$ s c. 2.54 x $10^{-2}$ m d. 5.23 x $10^{-6}$ g

Work Step by Step

a. 6.20 km to m. We know that in the International System of units (SI) 1km = $10^{3}$ m Therefore 6.20 km = 6.20 x $10^{3}$ m b. 1.98 ns to s. We know that in the International System of units (SI) 1ns = $10^{-9}$ s. Therefore 1.98 ns = 1.98 x $10^{-9}$ s . c. 2.54 cm to m. We know that in the International System of units (SI) 1cm = $10^{-2}$m. Therefore 2.54 cm = 2.54 x $10^{-2}$ m d. 5.23 µg to g. We know that in the International System of units (SI) 1µg = $10^{-6}$ g. Therefore 5.23 µg = 5.23 x $10^{-6}$ g
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