General Chemistry 10th Edition

Published by Cengage Learning
ISBN 10: 1-28505-137-8
ISBN 13: 978-1-28505-137-6

Chapter 1 - Chemistry and Measurement - Questions and Problems - Page 35: 1.72

Answer

$t_{F}$ = $-369^{0}$F

Work Step by Step

Apply the formula to convert Ceslius to Fahrenheit: $t_{F}$ =($t_{C}$ x$\frac{9^{0}F}{5^{0}C}$) +$32^{0}$F We know $t_{C}$ = $-222.7^{0}$C, so : $t_{F}$ =($-222.7^{0}$C x$\frac{9^{0}F}{5^{0}C}$) +$32^{0}$F $t_{F}$ = $-400.9^{0}$F+$32^{0}$F $t_{F}$ = $-368.9^{0}$F $t_{F}$ = $-369^{0}$F
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