Answer
a. $t_{C}$ = $11^{0}$C
b. $t_{C}$ = $-24^{0}$C
c. $t_{F}$ = $-42^{0}$F
d. $t_{F}$ = $72^{0}$F
Work Step by Step
a. We can convert temperature in Fahrenheit into Celsius, by applying the formula:
$t_{C}$ = $\frac{5^{0}C}{9^{0}F}$ x ($t_{F}$-$32^{0}$F)
We know $t_{F}$ = $51^{0}$F , so we can write:
$t_{C}$ = $\frac{5^{0}C}{9^{0}F}$ x ($51^{0}$F-$32^{0}$F)
$t_{C}$ = $\frac{5^{0}C}{9^{0}F}$ x$19^{0}$F
$t_{C}$ = $10.6^{0}$C
$t_{C}$ = $11^{0}$C
b. Apply the formula:
$t_{C}$ = $\frac{5^{0}C}{9^{0}F}$ x ($t_{F}$-$32^{0}$F)
We know $t_{F}$ = $-11^{0}$F , so we can write:
$t_{C}$ = $\frac{5^{0}C}{9^{0}F}$ x ($-11^{0}$F-$32^{0}$F)
$t_{C}$ = $\frac{5^{0}C}{9^{0}F}$ x($-43^{0}$)F
$t_{C}$ = $-23.9^{0}$C
$t_{C}$ = $-24^{0}$C
c. Apply the formula to convert Ceslius to Fahrenheit:
$t_{F}$ =($t_{C}$ x$\frac{9^{0}F}{5^{0}C}$) +$32^{0}$F
We know $t_{C}$ = $-41^{0}$C, so :
$t_{F}$ =($-41^{0}$C x$\frac{9^{0}F}{5^{0}C}$) +$32^{0}$F
$t_{F}$ = $-73.8^{0}$F+$32^{0}$F
$t_{F}$ = $-41.8^{0}$F
$t_{F}$ = $-42^{0}$F
d. Apply the formula to convert Ceslius to Fahrenheit:
$t_{F}$ =($t_{C}$ x$\frac{9^{0}F}{5^{0}C}$) +$32^{0}$F
We know $t_{C}$ = $22^{0}$C, so :
$t_{F}$ =($22^{0}$C x$\frac{9^{0}F}{5^{0}C}$) +$32^{0}$F
$t_{F}$ = $39.6^{0}$F+$32^{0}$F
$t_{F}$ = $71.6^{0}$F
$t_{F}$ = $72^{0}$F
