Chemistry: The Central Science (13th Edition)

Published by Prentice Hall
ISBN 10: 0321910419
ISBN 13: 978-0-32191-041-7

Chapter 10 - Gases - Exercises - Page 435: 10.41

Answer

4.879 atm

Work Step by Step

We have a 35.1g sample of CO2 so we convert this to moles. First we need the molar mass of CO2 as follows: Carbon is 12g/mol, O is 16g/mol 12 + 2*16 = 44g/mol 35.1g * (1mol/44g) = 0.798 moles The sample is placed in a 4L container and heated to 298K so we would have: PV = nRT or P = nRT/V = (0.798 mol * 0.0821 * 298K) / 4L = 4.879 atm
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