Work Step by Step
At STP condition, temp= 273K, P = 1 atm So by using the combined gas law PV = nRT and the n from question 10.43a, (n=0.42mol) (1 atm)(V) = (0.42 mol)(0.08201)(273K) Solving for V, V = (0.42)(0.08201)(273)/(1) = 9,4L
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