Chemistry: The Central Science (13th Edition)

Published by Prentice Hall
ISBN 10: 0321910419
ISBN 13: 978-0-32191-041-7

Chapter 10 - Gases - Exercises: 10.43b

Answer

9.40L

Work Step by Step

At STP condition, temp= 273K, P = 1 atm So by using the combined gas law PV = nRT and the n from question 10.43a, (n=0.42mol) (1 atm)(V) = (0.42 mol)(0.08201)(273K) Solving for V, V = (0.42)(0.08201)(273)/(1) = 9,4L
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