Answer
2.8 kg
Work Step by Step
One mole of hydrogen gas= 2.0 g of hydrogen gas
occupies 22.4 L volume at STP.
$\implies$ grams of hydrogen needed to fill 31000 L=
$\frac{2.0\,g}{22.4\,L}\times31000\,L=2800\,g$
$=2.8\,kg$
Chemistry: An Introduction to General, Organic, and Biological Chemistry (12th Edition)
by Timberlake, Karen C.
Published by
Prentice Hall
ISBN 10:
0321908449
ISBN 13:
978-0-32190-844-5
Chapter 8 - Section 8.7 - Partial Pressure (Dalton's Law) - Additional Questions and Problems - Page 279: 8.61
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