Chemistry: An Introduction to General, Organic, and Biological Chemistry (12th Edition)

Published by Prentice Hall
ISBN 10: 0321908449
ISBN 13: 978-0-32190-844-5

Chapter 8 - Section 8.7 - Partial Pressure (Dalton's Law) - Additional Questions and Problems - Page 279: 8.63

Answer

$-223^{\circ}$C

Work Step by Step

$P_{1}$ = 2.00 atm $T_{1}$ = (127+273) K = 400 K $P_{2}$ = 0.25 atm According to Gay Lussac's law, $\frac{P_{1}}{T_{1}}=\frac{P_{2}}{T_{2}}$ Or $T_{2}$ = $\frac{P_{2}T_{1}}{P_{1}} = \frac{0.25atm\times400K}{2.00atm}$ = 50. K = $(50-273)^{\circ}$C = $-223^{\circ}$C
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