Answer
4.46 g
Work Step by Step
One mole of $He $ = 4.00 g of $He$ has a volume of 22.4 L at STP.
$\implies$ grams of $He$ to give 25.0 L at STP
$=\frac{4.00\,g}{22.4\,L}\times25.0\,L=4.46\,g$
Chemistry: An Introduction to General, Organic, and Biological Chemistry (12th Edition)
by Timberlake, Karen C.
Published by
Prentice Hall
ISBN 10:
0321908449
ISBN 13:
978-0-32190-844-5
Chapter 8 - Section 8.7 - Partial Pressure (Dalton's Law) - Additional Questions and Problems - Page 279: 8.67a
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