Answer
$ 0.30 \space moles \space N_2$ reacted to produce 0.60 mole of $NH_3$.
Work Step by Step
1. Determine the conversion factor between $N_2$ and $NH_3$ moles:
According to the coefficients: 2 moles $NH_3$ = 1 mole $N_2$ .
$\frac{ 2 \space moles \space NH_3}{ 1 \space mole \space N_2}$ and $\frac{ 1 \space mole \space N_2}{ 2 \space moles \space NH_3}$
2. Use this conversion factor to calculate the amount of $N_2$ moles:
$0.60 \space moles \space NH_3$ $\times$ $\frac{ 1 \space mole \space N_2}{ 2 \space moles \space NH_3} = 0.30 \space moles \space N_2$
