Chemistry: An Introduction to General, Organic, and Biological Chemistry (12th Edition)

Published by Prentice Hall
ISBN 10: 0321908449
ISBN 13: 978-0-32190-844-5

Chapter 7 - Section 7.6 - Mole Relationships in Chemical Equations - Questions and Problems - Page 238: 7.52d

Answer

$0.080$ mole of $CO_2$ is produced from 0.100 mole of $O_2$.

Work Step by Step

1. Find the mole-mole conversion factors: According to the coefficients: 5 moles $O_2$ = 4 moles $CO_2$ $\frac{ 5 \space moles \space O_2}{ 4 \space moles \space CO_2}$ and $\frac{ 4 \space moles \space CO_2}{ 5 \space moles \space O_2}$ 2. Use the mole-mole conversion factors to calculate the amount of equivalent $CO_2$ in moles: $ 0.100$ mole $O_2 \times \frac{ 4 \space moles \space CO_2}{ 5 \space moles \space O_2} = 0.080$ mole $CO_2$
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