Answer
$ 0.93 \space moles \space NH_3$ are produced when 1.4 moles $H_2$ reacts.
Work Step by Step
1. Determine the conversion factor between $NH_3$ and $H_2$ moles:
According to the coefficients: 2 moles $NH_3$ = 3 mole $H_2$ .
$\frac{ 2 \space moles \space NH_3}{ 3 \space moles \space H_2}$ and $\frac{ 3 \space moles \space H_2}{ 2 \space moles \space NH_3}$
2. Use this conversion factor to calculate the amount of $NH_3$ moles:
$1.4 \space moles \space H_2$ $\times$ $\frac{ 2 \space moles \space NH_3}{ 3 \space moles \space H_2} = 0.93 \space moles \space NH_3$
